Why in this case a got an error all goroutins are asleep

Getting Help
1 
package main

import (
  "fmt"
)

func main() {
type EXP struct {
	A string
	b string
}

ch := make(chan EXP)
aw := EXP{"asdasd", "ASDASD"}
ch <- aw

for i := range ch {
	fmt.Println(i)
  }
}
2

Because ch is unbuffered, your main-goroutine will therefore sleep on ch <- aw until another go routine reads from the channel.

1 Like
3

You can’t perform both send and receive operations of a channel if the channel is unbuffered, within the same goroutine.

4

You can hardly read and write to the same channel from one gouroutine. The example above would reach deadlock even if the channel was buffered. Because range over a channel will lock then all items in channel is read.

5
6

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