I read this blog and this question and its answer, but found they are talking about single file only
// Parse our multipart form, 10 << 20 specifies a maximum
// upload of 10 MB files.
r.ParseMultipartForm(10 << 20)
// FormFile returns the first file for the given key `myFile`
// it also returns the FileHeader so we can get the Filename,
// the Header and the size of the file
file, handler, err := r.FormFile("myFile")
if err != nil {
fmt.Println("Error Retrieving the File")
fmt.Println(err)
return
}
defer file.Close()
How can I upload multiple files at one shoot?
If I have the below JavaScript code that upload multiple files, how can I read handle it in GO server
const formData = new FormData();
const photos = document.querySelector('input[type="file"][multiple]');
formData.append('title', 'My Vegas Vacation');
for (let i = 0; i < photos.files.length; i++) {
formData.append('photos', photos.files[i]);
}
fetch('https://example.com/posts', {
method: 'POST',
body: formData,
})
.then(response => response.json())
.then(result => {
console.log('Success:', result);
})
.catch(error => {
console.error('Error:', error);
});