How can i get top 3 most popular words from []string

[JustinObanor (Justin)]

https://play.golang.org/p/4KqiG6MR5Id
how can i get top N used words in a []string w/o getting the other words? commented in the code how the result might look like.
This is what it looks like just for counting. But im trying to get the top 3 frequent words
https://play.golang.org/p/Jr8SyZjpi_l

[Yamil_Bracho]

1. Modify rangeMap to receive a parameter that indicates how many top values you want to return

2. Use this code

   func rangeMap(s []string, count int) map[string]int {
       words := strings.Split(strings.Join(s, ""), " ")
   
    // count occurences	
    m := make(map[string]int)
    for _, word := range words {
    	_, ok := m[word]
    	if !ok {
    	  m[word] = 1
    	} else {
    	  m[word]++
    	}
    }
    
    // Takes max values
    counts:= make(map[string]int)
    for key, value := range m {
       if value > 0  {
           counts[key] = value
       }
    }
    
    // Sorts By Value
    keys := make([]string, 0, len(counts))
    for key := range counts {
    	keys = append(keys, key)
    }
    sort.Slice(keys, func(i, j int) bool { return counts[keys[i]] > counts[keys[j]] })
   
    // Builds result map	
    result := make(map[string]int)
    for _, key := range keys {
       result[key] = counts[key]
       count--
       if count == 0 {
          break
       }	
   
    }
    return result
    }

[JustinObanor (Justin)]

@Yamil_Bracho

result := make(map[string]int) for _, key := range keys { result[key] = counts[key] count-- if count == 0 { break }

Thanks for the solution, but im not really sure what is happening here after we range over our sorted string.
The results part

[Yamil_Bracho]

Ok
After sort the keys, we will build a map to return the results to the caller. This code is

// Builds result map
result := make(map[string]int)
for _, key := range keys {
	result[key] = counts[key]
	count--
	if count == 0 {
		break
	}
}
return result

/count is the number of items you want to return. You mention 3 top, so count is that number.
However, the tricky part is the sort

// Takes max values
	counts := make(map[string]int)
	for key, value := range m {
		if value > 1 {
			counts[key] = value
		}
	}

This part takes only the words that are repeated in the string. I wrote 0 (value > 0) but the number should be 1 (value > 1)

Afther this, we build a slice with the keys of the above map. The sort routune takes the count of each of those keys to order this slice.

[Christophe_Meessen]

Here it is: https://play.golang.org/p/UeegCwmMUbV

You correctly identified the first part of the solution. You first need to count the words and for this you use a map.

What is missing, is the second step. To get the three most frequent words, you need to sort the words by count. For this you need a slice of word-count pairs that you may then sort.

Once the slice is sorted, the three first entries is what you want to print.