look at this code from blog.golang.org/pipelines about fun-in fun-out pattern, so if you will look at merge function then you will see that it just passing incoming two channel’s value onto another channel and return that channel , we are passing to the merge 2 channels with the same values (4, 9) and getting back one channel
so when we iterate throw this new coming channel output is only 4, 9 or 9, 4
and my question is the following
why it does not print another 4, 9 ( why the out put is not 4,9, 4,9) why it prints value only from 1 channel insted of printing value from both channels what we have send to the merge function.
`
func main() {
in := gen(2, 3)
// Distribute the sq work across two goroutines that both read from in.
c1 := sq(in)
c2 := sq(in)
// Consume the merged output from c1 and c2.
for n := range merge(c1, c2) {
fmt.Println(n) // 4 then 9, or 9 then 4
}
}
func gen(nums ...int) <-chan int {
out := make(chan int)
go func() {
for _, n := range nums {
out <- n
}
close(out)
}()
return out
}
func sq(in <-chan int) <-chan int {
out := make(chan int)
go func() {
for n := range in {
out <- n * n
}
close(out)
}()
return out
}
func merge(cs ...<-chan int) <-chan int {
var wg sync.WaitGroup
out := make(chan int)
// Start an output goroutine for each input channel in cs. output
// copies values from c to out until c is closed, then calls wg.Done.
output := func(c <-chan int) {
for n := range c {
out <- n
}
wg.Done()
}
wg.Add(len(cs))
for _, c := range cs {
go output(c)
}
// Start a goroutine to close out once all the output goroutines are
// done. This must start after the wg.Add call.
go func() {
wg.Wait()
close(out)
}()
return out
}
`