Go program fail to interrupt process

Getting Help
1

Hi,
I’m running go version go1.9.3 darwin/amd64.
The code :

cmd := exec.Command(command, options.Args...) // bash process - ruby running forever
cmd.Start()
go cmd.Wait() // I can see my process up and get to it
time.Sleep(20 * time.Second)
syscall.Kill(cmd.Process.Pid, syscall.SIGINT) // ruby process get the signal and do nothing with it
time.Sleep(5 * time.Second)
cmd.Process.Signal(os.Interrupt) // ruby process get the signal and do nothing with it
time.Sleep(5 * time.Second)
syscall.Kill(p.cmd.Process.Pid, syscall.SIGTERM) // ruby process get the signal and do nothing with it
time.Sleep(5 * time.Second)
syscall.Kill(p.cmd.Process.Pid, syscall.SIGKILL) //This will kill the process
//cmd.Process.Kill() //This will kill the process
//cmd.Process.Signal(os.Kill) //This will kill the process

The problem is that the only way to stop the process is killing it immediately (equal to kill -9 )
Manually it is possible to interrupt or terminate the process and not to kill it.

I would like to understand how to interrupt the process in a way it will work

2

What to you mean by manual kill? Ctrl-C or “kill pid”?

3

manually kill -2 is working fine

4 
if err := cmd.Process.Kill(); err != nil {
    log.Fatal("failed to kill: ", err)
}

There is also Signal method on Process.

https://golang.org/src/os/exec.go?s=3842:3884#L110

5

syscall.Kill also returns an error, check it.

6

This kill is working, but its equals to kill -9 and not to interrupt.
I would like to release the process in a softer way.

7

Just use cmd.Process.Signal(os.Interrupt)

8

tried, the process get the signal and the process not stop

9

But that’s up to the process receiving the signal.

10

Yes, it must be the process then, thy some other process which handles signals for sure.

11

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