Getting the owner of a file

Getting Help
1

What is the Go-way to obtain the owner of a file? I spent some time on this yesterday but found no simple solution. On poster suggested fi.Sys().(*syscall.Stat_t).Uid.

Some posts suggested that since there is no operating system independent way to do this Go has left it unimplemented. In particular there would be differences between Windows and GNU/Linux in this area.

I’ll continue to work on this today and reply to my post with the solution (if I can find one) that I wound up using.

Kind regards, -Randy

2

Update: I’ve decided to go with fi.Sys().(*syscall.Stat_t).Uid approach. Along the way I was reminded/learned a few things. user.Uid is a string. To get a uint32 from it one must use strconv.ParseUint() and unit32().

I also just learned about go doc. As in:
go doc strconv
Cheers, -Randy

1 Like
3

One really simple way is to use GitHub - bitfield/script: Making it easy to write shell-like scripts in Go –

package main

import (
	"fmt"
	"github.com/bitfield/script"
)

func main() {
	owner, _ := script.Exec("ls -alhrt /usr/local/bin").Match("tcpscan").Column(3).String()
	fmt.Println("Owner of the file is", owner)
}

Output:

go run main.go
Owner of the file is rmasci

If you were on windows, you’d just check GOOS if it’s windows, mac, linux and substitute the command accordingly.

4

In that example, the file I was looking for was called ‘tcpscan’ – substitute for the file you’re looking for.

5

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