Convert 32 digit value to String Value

Getting Help
1

Hi Team,
I want to convert below 32 digit number into String Value using Go.

01000111000111111111111100011001

is there any method available for this?

Thanks,
Rajapandian.B

2

What is the expected result? Which encoding is used?

  • ASCII
  • LATIN-1
  • UTF-8
  • UTF-16-LE
  • UTF-16-BE
  • UTF-32
3

Same value only. I need 32 digit as String and I will do some split operation.

4

So you expect this?

"01000111000111111111111100011001"
5

Yes

6

How does 01000111000111111111111100011001 enter your system? It is not a valid int. Please show us a code sample that you use to get this number.

7

Here you go:

package main

import (
	"fmt"
)

func main() {
	i := 1193279257
	s := fmt.Sprintf("\"%b\"", i)
	fmt.Println(s)
}

Output:

"1000111000111111111111100011001"
1 Like
8

Thanks .It is working.I am trying to prepend “0” at the beginning.I want the below output

“01000111000111111111111100011001”.

i := 1193279257
s := fmt.Sprintf(""%b"", i)
fmt.Println(“0” +s)

But i am getting below output

0"1000111000111111111111100011001"

Thanks,
Rajapandian.B

9

%032b for binary, 32 digits, zero padded.

Fully documented here: https://golang.org/pkg/fmt/

1 Like
10

Thanks.But How to call this

fmt.Sprintf("%032b\n", s)

s is having this value -1000111000111111111111100011001 .

i am getting below output

%!b(string=“1000111000111111111111100011001”)

THanks,
Raja

11

fmt.Sprintf("%032b\n", s) gives you a string. It doesn’t output anything. How are you producing the output?

12

This topic was automatically closed 90 days after the last reply. New replies are no longer allowed.