Printing a function value

[hyousef (Hasan Yousef)]

Learning Interface in GO and made the below code:

package main

import "fmt"

type I interface {
	fullName() string
}
type Person struct {
	fname, lname string
}

func (p Person) fullName() string { // can not accept: (p *Person)
	return p.fname + p.lname
}

func main() {
	var name string = `hasan`
	var p I = Person{fname: name, lname: `yousef`}
	fmt.Printf("Your full name is: %v", p.fullName)

}

The output I got is:

Your full name is: 0x49c560

Which is not as expected, what is the 0x49c560 and how to get the correct output printed as string?

[Yamil_Bracho]

You defined fullName as a function that retturns a string so change your call to

fmt.Printf("Your full name is: %v", p.fullName())

[kron4eg (Artiom Di)]

Yep, exactly as @Yamil_Bracho pointed out, you’ve forgot to actually call the function.

As in Go functions (and methods obviously) are first-class citizens, they can be used as values (assigned, passed as arguments, etc), that’s why it’s completely “legal” to do what you did, but this has different meaning

[thenorthnate (Nathan North)]

One other thing - your comment that says // can not accept: (p *Person) isn’t quite true - you actually can have pointer receivers! Your function could look like:

func (p *Person) fullName() string {
	return p.fname + p.lname
}

As long you changed the line in your main function to:
var p I = &Person{fname: name, lname: "yousef"}
(Note the & sign before the word Person)