Go - yaml help. Parse value for internships is empty

[Arkaprabha_Majumdar]

package main

import (
	"fmt"
	"io/ioutil"
	"log"

	"gopkg.in/yaml.v2"
)

type instanceConfig struct {
	Name    string `yaml:"Name"`
	Address string `yaml:"Address"`
	Phone   int    `yaml:"Phone"`
	WFH     bool

	Internships string `yaml:"Internships"`
}

func (c *instanceConfig) Parse(data []byte) error {
	return yaml.Unmarshal(data, c)
}

func main() {
	data, err := ioutil.ReadFile("file.yml")
	if err != nil {
		log.Fatal(err)
	}
	var config instanceConfig
	if err := config.Parse(data); err != nil {
		log.Fatal(err)
	}
	fmt.Printf("%+v\n", config)
}

I am trying to parse yaml in GO. Two problems:

1. why is it necessary to define each mapping in yaml like yaml:"Name" …it cant just map the first item to first key?

2. how can I output the Internships as a list within the yaml? Adding 'Internships list yaml:"Internships"’ did not work at all.

   ---

   Name: “Arka”
   Address: “India”
   Phone: 100
   WorkFromHome: true
   Mail: “abc@hotmail.com”

   Internships:
   - JournalDev
   - MNO
   - ABC
   - XYZ
   Education:
   MSc: 7.6
   BSc: 8.1
   XII: 9
   Courses:
   Udemy: 15
   Coursera: 3
   References: “Mr. QWERTY, XYZ”

[NobbZ (Norbert Melzer)]

@Arkaprabha_Majumdar

why is it necessary to define each mapping in yaml like yaml:"Name" …it cant just map the first item to first key?

For built-in JSON lib it is the way you describe, perhaps the author of the yaml decoder hasn’t implemented it (yet).

@Arkaprabha_Majumdar

how can I output the Internships as a list within the yaml? Adding 'Internships list yaml:"Internships" ’ did not work at all.

Internships []string `yaml:"Internships"` should totally do. At least that is how it works in the built-in JSON decoder.